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So is that a yes or no to the choosing to figure out if shatterstar is within six of random other figure for counting his power?
I feel like this should work, since tellus's power means you are not obligated to use leech's square for counting.
Also you aren't obligated to use every possible choice, you just always need to choose SOMETHING (including the original figure) each time you count squares or draw LoF.
The "you can't NOT count from leech's occupied square" problem is why I wanted to know whether or not his power actually interacts with Tellus's ability properly. I could imagine MisterId ruling that AoE effects all suffer the same problem that Tellus's own trait does, whether you count from other squares or not, what is "within N squares" is NOT variable.
As already stated.
Quote : Originally Posted by normalview
Shatterstar is within 6 squares of Leech; Tellus does not change that. Tellus expands the potential range/area of things. He does not shrink them.
(A is any friendly, T is tellus, L is leech, O is an opposing figure, S is shatterstar, and P is something less points than shatterstar and friendly)
Can you have shatterstar teleport here, while still locking down O from taking power actions?
He is only within leech's 6 squares if leech chooses to count from T, S, or P, but not if leech just counts from himself or A.
So I can lock down O, because he is within 6 of T, but I can choose to also NOT lock down S because he isn't naturally within 6 (so no shrinkage by selecting leech himself to count from).
(A is any friendly, T is tellus, L is leech, O is an opposing figure, S is shatterstar, and P is something less points than shatterstar and friendly)
Can you have shatterstar teleport here, while still locking down O from taking power actions?
He is only within leech's 6 squares if leech chooses to count from T, S, or P, but not if leech just counts from himself or A.
So I can lock down O, because he is within 6 of T, but I can choose to also NOT lock down S because he isn't naturally within 6 (so no shrinkage by selecting leech himself to count from).
Does this work?
Shatterstar is within 6 of T and P in that diagram. A is too far away to be of use (it is 7 away from O). So, as currently arranged, there is no way to get O and not also get Shatterstar.
Reposition A slightly, and then you've got something.
Also, I should note that nothing prevents Shatterstar from using X-Portal to be placed adjacent to Leech as long as he was not within Leech's effect when he was given the power action. So even with the current arrangement you have now, Shatterstar could have appeared in that position so long as he came from somewhere else (presumably, some place not on your diagram).
Shatterstar is within 6 of T and P in that diagram. A is too far away to be of use (it is 7 away from O). So, as currently arranged, there is no way to get O and not also get Shatterstar.
Reposition A slightly, and then you've got something.
Also, I should note that nothing prevents Shatterstar from using X-Portal to be placed adjacent to Leech as long as he was not within Leech's effect when he was given the power action. So even with the current arrangement you have now, Shatterstar could have appeared in that position so long as he came from somewhere else (presumably, some place not on your diagram).
"Shatterstar is within 6 of T and P in that diagram." correct, but neither T nor P are Leech, and leech is NOT required to use either of them for drawing lines of fire. (he can [must] choose A character, there is no specification saying that he must choose a particular character.
O and shatterstar are not going to be using power actions at the same time, and leech's power is continuously checking, which means that who I choose to draw LoF from at any given moment can change (assuming that Leech can transfer those squares through tellus) on a whim.
When the 'game' asks "is O within the power's range" the game then asks "who is leech counting from", which leads to the answer of "tellus", which leads to the answer of "No Power actions for you".
Yet when the game asks "is S within the power's range" the game then asks us who leech is counting from, to which leech's controller would say "I am counting from leech", so the game says "Shatterstar is not dampened".
This wholly unintuitive way of things working is why I think "does leech work with tellus?" is NOT actually an obvious 'yes', and may be a technical 'no' for the sole reason that it causes some really strange problems in regards to timing (in a sense, it is the same kind of problem that the wild-card TAs used to have way back when, and that I remember hearing Uatu the Watcher having prior to some errata).
Allowing leech and tellus to work together can cause the above to happen, where because Leech's controller gets to choose who to count from, shatterstar is not within the AOE, yet the opposing character who the same distance from leech WILL be within the AOE because leech will obviously just choose a different starting point.
"Shatterstar is within 6 of T and P in that diagram." correct, but neither T nor P are Leech, and leech is NOT required to use either of them for drawing lines of fire. (he can [must] choose A character, there is no specification saying that he must choose a particular character.
No, he isn't required to us T or P. But if he wants to get O, he can't use A, either. A is too far away. So if he wants to get O, he needs to use either T or P... and thus also get Shatterstar.
Quote
O and shatterstar are not going to be using power actions at the same time, and leech's power is continuously checking, which means that who I choose to draw LoF from at any given moment can change (assuming that Leech can transfer those squares through tellus) on a whim.
When the 'game' asks "is O within the power's range" the game then asks "who is leech counting from", which leads to the answer of "tellus", which leads to the answer of "No Power actions for you".
Yet when the game asks "is S within the power's range" the game then asks us who leech is counting from, to which leech's controller would say "I am counting from leech", so the game says "Shatterstar is not dampened".
This wholly unintuitive way of things working is why I think "does leech work with tellus?" is NOT actually an obvious 'yes', and may be a technical 'no' for the sole reason that it causes some really strange problems in regards to timing (in a sense, it is the same kind of problem that the wild-card TAs used to have way back when, and that I remember hearing Uatu the Watcher having prior to some errata).
Allowing leech and tellus to work together can cause the above to happen, where because Leech's controller gets to choose who to count from, shatterstar is not within the AOE, yet the opposing character who the same distance from leech WILL be within the AOE because leech will obviously just choose a different starting point.
There is no timing issue. I think you simply miscounted with your placement of A. Go back and reread what I wrote and then let me know if you still have questions.
Shatterstar is within 6 of T and P in that diagram. A is too far away to be of use (it is 7 away from O). So, as currently arranged, there is no way to get O and not also get Shatterstar.
So, what is the Duration then on Tellus' effect? If I say "I'm going to count squares from P" does that mean until Tellus' loses that power or the figure is no longer within 4 from Tellus? And if that IS the case does that mean that if we replace Leech with a primary Attacker that if they counted range from P's square they must do so every time they attack? And if the second answer is NO then does that mean I can say "On your turns I'm counting Leech's power from P's square. On my turns I'm counting it from Leech's square."?
aqhoffman- greatest post possibly ever
jtallday- Jon I wouldn't challenge you if I wasn't sure you are wrong cuz I don't have that kind of energy.
So, what is the Duration then on Tellus' effect? If I say "I'm going to count squares from P" does that mean until Tellus' loses that power or the figure is no longer within 4 from Tellus? And if that IS the case does that mean that if we replace Leech with a primary Attacker that if they counted range from P's square they must do so every time they attack? And if the second answer is NO then does that mean I can say "On your turns I'm counting Leech's power from P's square. On my turns I'm counting it from Leech's square."?
I am under the impression that you get to re-choose where you are drawing LoF/counting squares from EACH AND EVERY time you need to do so.
It doesn't say "choose for a character, and then abide by that choice for future actions/decisions", just just says "when you would do A, you choose a character to count from".
There is no limiting language that even remotely suggests that once you have made a choice in one instance, that it has ANY bearing on choices in later instances.
Quote : Originally Posted by normalview
No, he isn't required to us T or P. But if he wants to get O, he can't use A, either. A is too far away. So if he wants to get O, he needs to use either T or P... and thus also get Shatterstar.
There is no timing issue. I think you simply miscounted with your placement of A. Go back and reread what I wrote and then let me know if you still have questions.
Quote : Originally Posted by firlz
He is only within leech's 6 squares if leech chooses to count from T, S, or P, but not if leech just counts from himself or A.
I am not claiming A is close enough for anything to work. My question remains even if A is removed. (I am SPECIFICALLY stating that A is too far away for squares to get to O, because he is 7 away). In the above quoted statement, I am stating "T, S, and P are all within 6 of O, and inside tellus's AoE" and also stating "A and L are NOT within 6 of O, but are within Tellus's AoE".
My question IS ultimately one of timing because it raises the following issue.
If I am allowed to choose which character to count from whenever I need to count stuff, why does my choosing of T some of the time require me to continue choosing T at other times?
Similarly to jonidschultz's point, why is it that if I use A to draw LoF to O for tellus's probability control one time, that I would have to draw his LoF from A EVERY time?
Tellus's power doesn't say "make a choice before you need to count to something..." and then stick you with that choice forever. He just replaces the 'normal' counting machinery when it would apply, and ONLY at that point.