So, in planning a possible team to play around with, I wanted to know if my thoughts on a 6 sin, third round Shazam! attempt were possible. I listed the hopeful turn of events below and am wondering if this is plausible or am I only looking @ 5 sins by turn 3.

Thanks gang.

IIM103 Absorbing Man
14 JLTWR102 Rock of Eternity
2 JLTWR102A Envy
2 JLTWR102B Sloth
2 JLTWR102C Pride
2 JLTWR102D Greed
2 JLTWR102E Lust
2 JLTWR102F Wrath
2 JLTWR102G Gluttony
58 AVAS037 Manifold
33 FL007 S.T.A.R. Labs Technician
25 WOL060P Black Hand (for Absorbing Man or Manifold)
(Maybe a Bystander for 3 points as well)
297

Tactics
Turn 1
- Start of turn: Attach Sin #1
- Free Action, Sidestep Lab Tech to second tier
- Action 1: TK AM to Sin #2 (Spot 1) with Lab Tech
- Free Action: Attach Sin #2 (sidebar)
- Action 2: Move AM to Sin #3 (Spot 2)
- Action 3: Move Manifold to second tier

Turn 2
- Start of turn: Attach Sin #4 (sidebar)
- Free Action: Attach Sin #3 (Spot 2)
- Action 1: Push TK AM to Sin #5 (Spot 3) with Manifold
- Clear other tokens (including Champion)

Turn 3
- Start of turn: Attach Sin #6 (sidebar)
- Free Action: Attach Sin #5 (Spot 3) <-- this is the step I'm unsure of.
- Start of turn: Roll for Shazam
- Hopefullg go to town with AM

I think it's pretty essential to have all 7 sins for the RoE since, even with all 7 attached, you need to roll high. Rolling a 9 with the 7 attached is not easy. Rolling a 10 with 6 attached will be even more difficult. It's a sound plan to have AM be really hard to kill while you're picking up the Sins, but you really need to put 7 in there I think.

Well, there will be 7 by turn 4. But I was aiming for at least better odds by turn 3. I just was not sure of that order of the steps, is it valid or out of order?